The average translational kinetic energy of air molecules is 0.040 eV (1 eV = 1.6 × 10 –19 J). Calculate the temperature of the air. Boltzmann constant κ = 1.38 × 10 –23 J K –1 .

Question

Philoid · Accepted Answer

We know that kinetic energy of ideal gas is given by

…. (I)

Where K. E=kinetic energy of gas

k_B = Boltzmann constant=1.38 × 10^–23 J K^–1.

T = temperature of gas

In kinetic theory of ideal gas, molecule of gas is moving in straight line.

Hence, they will only have translational kinetic energy.

Given

K. E=0.040 eV

We know that

1 eV = 1.6 × 10^–19J

0.040eV=0.040J

From equation (I) we can write

Therefore, the temperature of gas is 309.2K.

The average translational kinetic energy of air molecules is 0.040 eV (1 eV = 1.6 × 10–19J). Calculate the temperature of the air. Boltzmann constant κ = 1.38 × 10–23 J K–1.

The average translational kinetic energy of air molecules is 0.040 eV (1 eV = 1.6 × 10^–19J). Calculate the temperature of the air. Boltzmann constant κ = 1.38 × 10^–23 J K^–1.