The temperature and relative humidity in a room are 300 K and 20% respectively. The volume of the room is 50 m 3 . The saturation vapor pressure at 300 K is 3.3 kPa. Calculate the mass of the water vapor present in the room.

Question

Philoid · Accepted Answer

Given

Temperature T=300K

Relative humidity=20%

Volume of room= 50m³

Saturation vapor pressure at 300 K is 3.3 kPa=3.3Pa.

P=0.23.310³=660Pa

Molar mass of water H₂O =2+16=18g

Applying ideal gas equation

PV=nRT

Where V= volume of gas

R=gas constant =8.3JK^-1mol^-1

T=temperature

n=number of moles of gas

P=pressure of gas.

Number of moles n=

m=238.55g

Mass of water vapor present in the room=238.55g.

The temperature and relative humidity in a room are 300 K and 20% respectively. The volume of the room is 50 m3. The saturation vapor pressure at 300 K is 3.3 kPa. Calculate the mass of the water vapor present in the room.

The temperature and relative humidity in a room are 300 K and 20% respectively. The volume of the room is 50 m³. The saturation vapor pressure at 300 K is 3.3 kPa. Calculate the mass of the water vapor present in the room.