The magnetic intensity H at the centre of a long solenoid carrying a current of 2.0 A, is found to be 1500 A m–1. Find the number of turns per centimeter of the solenoid.

Given:


Current in the solenoid I=2A


Magnetic intensity H at the centre =1500Am-1


We know that ,


Magnetic field produced by solenoid at the centre (B) is given by


(i)


Where,


n=no. of turns per unit length


I=current in the solenoid


μ0=absolute permeability of vacuum


also magnetizing field intensity (H) in the absence of any material is given by



Where


B=net magnetic field


Putting the value of eqn.(i)



Putting the values of H and I we get



turns/m


turns/cm


Therefore no. of turns per cm of the solenoid is 7.5 turn/cm


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