The magnetic intensity H at the centre of a long solenoid carrying a current of 2.0 A, is found to be 1500 A m–1. Find the number of turns per centimeter of the solenoid.
Given:
Current in the solenoid I=2A
Magnetic intensity H at the centre =1500Am-1
We know that ,
Magnetic field produced by solenoid at the centre (B) is given by
(i)
Where,
n=no. of turns per unit length
I=current in the solenoid
μ0=absolute permeability of vacuum
also magnetizing field intensity (H) in the absence of any material is given by
Where
B=net magnetic field
Putting the value of eqn.(i)
Putting the values of H and I we get
turns/m
turns/cm
Therefore no. of turns per cm of the solenoid is 7.5 turn/cm