A rod is inserted as the core in the current-carrying solenoid of the previous problem. (a) What is the magnetic intensity H at the centre? (b) If the magnetization I of the core is found to be 0.12 A m –1 , find the susceptibility of the material of the rod. (c) Is the material paramagnetic, diamagnetic or ferromagnetic?

Question

Philoid · Accepted Answer

Given:

Magnetization field intensity H=1500Am^-1

Magnetization of the core I=0.12Am^-1

If a rod is inserted in the core of current carrying solenoid then

As the solenoid and the rod are long and we are interested in magnetic intensity at the centre, the end effects may be neglected. There is no effect of rod on magnetic intensity at the centre. Therefore, value of magnetization intensity remains same.

Therefore, magnetic intensity H at the centre is 1500Am^-1

The magnetization I is given by formula

Where,

=susceptibility of the material

H=magnetization intensity

Putting the value of I and H we get

Therefore, susceptibility of material of rod is given by 8× 10^-5

Since and less than 1 the material is paramagnetic.

Therefore, the material is paramagnetic.