A charged particle is accelerated through a potential difference of 12 kV and acquires a speed of 1.0 × 108ms–1. It is then injected perpendicularly into a magnetic filed of strength 0.2 T. Find the radius of the circle described by it.
Given-
Applied potential difference to the charged particle , V = 12 kV = 12 × 103 V
Speed acquire by the charged particle, v =1.0 × 106 m s−1
Perpendicular Magnetic field B = 0.2 T
We know
The kinetic energy acquired by the particle is produced due to
applied potential difference, hence
and
where,
m is the mass of a proton
v= velocity of the particle
B = magnetic force
q= charge on the particle