A 50 turn circular coil of radius 2.0 cm carrying a current of 5.0 A is rotated in a magnetic field of strength 0.20 T.
(a) What is the maximum torque that acts on the coil?
(b) In a particular position of the coil, the torque acting on it is half of this maximum. What is the angle between the magnetic field and the plane of the coil?
Given-
No. of turns of the coil, n = 50
Magnetic field intensity, B = 0.20 T = 2 × 10−1 T
Radius of the coil, r = 0.02 m = 2 × 10−2 m
Magnitude of current =5 A
We know that torque acting on a rectangular coil having n turns is given by
Where
B= applied magnetic field
A= area of rectangular loop
I = current flowing through coil
= angle between the area vector and magnetic field
Torque is maximum if
θ = 90°.
Given that ,
So, the angle between the magnetic field and the plane of coil is given by -
