An aluminum vessel of mass 0.5 kg contains 0.2 kg of water at 20°C. A block of iron of mass 0.2 kg at 100°C is gently put into the water. Find the equilibrium temperature of the mixture. Specific heat capacities of aluminum, iron and water are 910 J kg –1 K –1 ; 470 J kg –1 and 4200 J kg –1 K –1 respectively.

Question

Philoid · Accepted Answer

Given;

Mass of aluminium=0.5kg

mass of water=0.2kg

Mass of iron=0.2kg

temperature of aluminium vessel and water=20⁰c

Temp of iron=100⁰c

heat capacity of aluminium=910 J/kg-k

heat capacity of iron=470J/kg-k

heat capacity of water=4200J/kg-k

Formula used:

ΔQ=mCΔT

ΔQ=heat exchange

ΔT=tempeature change

M=mass

C=heat capacity

let the dinal temperature of the mixture be T;

so;

as

heat gain by aluminum and water=heat loss by iron

T=298.41⁰k