A piece of iron of mass 100 g is kept inside a furnace for a long time and then put in a calorimeter of water equivalent 10g containing 240 g of water at 20°C. The mixture attains an equilibrium temperature of 60°C. Find the temperature of the furnace. Specific heat capacity of iron = 470 J kg –1 °C – .

Question

Philoid · Accepted Answer

Given:

Mass of iron=100g

water equivalent of calorimeter=10g

Mas of water =240g

temp of surface=0⁰c

S_iron=470J/kg-k

Formula Used:

ΔQ=mCΔT

ΔQ=heat exchange

ΔT=tempeature change

M=mass

C=heat capacity

Heat gained by water = heat lost by iron

So

T=953.61⁰C