The temperatures of equal masses of three different liquids A, B and C are 12°C, 19°C and 28°C respectively. The temperature when A and B are mixed is 16°C, and when B and C are mixed, it is 23°C. What will be the temperature when A and C are mixed?
Given:
Temp of A=12° c
Temp of B=19° c
Temp of C=28° c
Formula used:
ΔQ=MCΔT
ΔQ=heat exchange
ΔT=tempeature change
M=mass
C=heat capacity
Now;
When A and B are mixed
MA(16-12)=MB(19-16)
MB=4MA/3
Also;
When B and C are mixed
MB(23-19)=Mc(28-23)
MB=5Mc/4
So when A and C are mixed let the final temperature be T
MA(T-12)=Mc(28-T)
MB(T-12)=
MB(28-T)
15T-180=448-16T
T=20.3° C