Calculate the time required to heat 20 kg of water from 10°C to 35°C using an immersion heater rated 1000 W. Assume that 80% of the power input is used to heat the water. Specific heat capacity of water = 4200 J kg–1 K–1.
Given:
heat capacity of water = 4200 J kg–1 K–1.
Formula used:
ΔQ=MCΔT
ΔQ=heat exchange
ΔT=tempeature change
M=mass
C=heat capacity
Heat given by heater = heat taken by water
0.8× 1000× t=20× 4200× (35-10)
t=2625 s=43.75 minutes