A 50 kg man is running at a speed of 18 km h –1 . If all the kinetic energy of the man can be 9 used to increase the temperature of water from 20°C to 30°C, how much water can be heated with this energy?

Question

Philoid · Accepted Answer

Given:

Speed of man:5m/s

ΔT=10⁰C

Mass of man=50kg

Formula used:

Kinetic energy =1/2 mv²

ΔQ=MCΔT

ΔQ=heat exchange

ΔT=tempeature change

M=mass

C=heat capacity

Kinetic energy of person = heat absorbed by the water

625=M× 4200× (30-20)

M=0.01488kg

A 50 kg man is running at a speed of 18 km h–1. If all the kinetic energy of the man can be 9used to increase the temperature of water from 20°C to 30°C, how much water can be heated with this energy?

A 50 kg man is running at a speed of 18 km h^–1. If all the kinetic energy of the man can be 9used to increase the temperature of water from 20°C to 30°C, how much water can be heated with this energy?