A ball is dropped on a floor from a height of 2.0 m. After the collision it rises up to a height of 1.5 m. Assume that 40% of the mechanical energy lost goes as thermal energy into the ball. Calculate the rise in the temperature of the ball in the collision. Heat capacity of the ball is 800 J K–1.

Given:


Heat capacity of ball=800 J/K


Formula used:


Potential energy=mgh


M=mass


H=height


ΔQ=MCΔT


ΔQ=change in energi


ΔT=change in temperature


C=heat capacity


M=mass


So


Change in poteintial energy=0.5× g× M


Now;


Change in potential energy=change in energy


5M=MCΔT


5=800ΔT


0.0025⁰C=ΔT


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