Given:

Total charge in the cube =Q at the center

We know that,

By Gauss’s law, flux of net electric field through a closed surface equals the net charge enclosed by the surface divided by ϵ₀

From Gauss’s law we can conclude that total flux enclosed by the cube is given by

Since charge is placed at centre it is placed symmetrically with respect to all the faces of the cube . therefore we can say that equal flux passes through all the six surfaces.

∴ flux passing through each surface

⇒

Therefore flux of electric field passing through each of the six surfaces are equal and is given by Q/6ϵ₀