A long cylindrical wire carries a positive charge of linear density 2.0 × 10–6 C m–1. An electron revolves around it in a circular path under the influence of the attractive electrostatic force. Find the kinetic energy of the electron. Note that it is independent of the radius.
Given:
Linear charge density of wire=2.0× 10-6C=λ
We know that,
Electric field E due to a linear charge distribution of linear charge density λ at a distance r from the line is given by
….(i)
Now,
Magnitude of Force experienced by a charge q in an electric field of intensity E is given by
Here the charge particle is electron so the charge =q=e
Since this electron revolves around the wire in a circular path under the influence of this electrostatic force this force is equal to the centripetal force experienced by the electron
∴ …(ii)
Where,
m=mass of electron=9.1× 10-31kg
r=radius of orbit in which electron revolves
q=e=charge of electron=1.6× 10-19C
E=electric field due to line charge
V=velocity of electron
We know that ,
Kinetic energy of electron is given by
…(iii)
Where,
m=mass of electron
v=velocity of electron
from eqn,(ii) ,
Therefore kinetic energy of electron is given by
Putting value of E from eqn.(i)
Thus kinetic energy is independent of radius(r)
⇒ J
⇒ J
Therefore kinetic energy of electron while revolving around a cylindrical charge is given by 2.88× 10-17J and it is independent of radius.