When a dielectric slab is gradually inserted between the plates of an isolated parallel-plate capacitor, the energy of the system decreases. What can you conclude about the force on the slab exerted by the electric field?
When a dielectric slab is gradually inserted between the plates of an isolated parallel-plate capacitor, the energy of the system come out to be a linear function of xdisplacement of the slab inside capacitor measured from the center of the plate).
since x decreases, the energy of the system decreases.
We know that
Where
is the rate of change of potential energy function with x
-ve sign indicates that force is in negative direction when energy increases with respect to x)
Therefore, Force on the slab exerted by the electric field is constant and positive.