Two capacitors each having capacitance C and breakdown voltage V are joined in series. The capacitance and the breakdown voltage of the combination will be
Two capacitance each having capacitance C and breakdown voltage V joined in series.
The general formula for effective capacitance of a series combination of n capacitors is given by
The equivalent capacitance of two capacitors in series is given by
Where
C1 is the capacitance of the first capacitor
C2 is the capacitance of the second capacitor
On Solving for C, we get
Since, C1=C2=C
Putting the values of C1 and C2, we get
Also, Capacitors in series have same amount of charge
∴ Q1=Q2=Q
Therefore, potential difference across both the capacitors are also equal to V
So, the voltage across the system is the sum of voltage across each capacitor.
Therefore, the breakdown voltage of the combination =V+V⇒ 2V
Thus, the capacitance and breakdown voltage of the combination is C/2 and 2V respectively