If the capacitors in the previous question are joined in parallel, the capacitance and the breakdown voltage of the combination will be

Given:

Two capacitors of capacitance C each and breakdown voltage V connected in parallel



Explanation:


The general formula for effective capacitance of a series combination of n capacitors is given by



The equivalent capacitance of two capacitors connected in parallel are given by



Where


C1 is the capacitance of the capacitor C1


C2 is the capacitance of the capacitor C2


Here C1=C2=C


Putting the values in the above formula, we get


∴ Ceq=C+C=2C


Since, potential difference across capacitors in parallel are equal


Therefore voltage across the system is equal to the voltage across a single capacitor.


Therefore, breakdown voltage of the combination =V

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