A dielectric slab is inserted between the plates of an isolated capacitor. The force between the plates will
We know that,
Force between the plates of the capacitor is given by
Where,
Q=charge on the capacitor
A=area of plates
Derivation:
Suppose charge Q and -Q are provided on plates of capacitor of area A.
Since, F=QE
Where
Q is the test charge on the point charge
E is the electric field intensity.
Field due to charge Q on one plate is
Force on the plate with charge -Q will be
Considering magnitude, each plate applies a force of
Each.
On increasing a dielectric slab between the plates of the capacitor, the charge on the plates remains constant as the plates are isolated) .
Since, area of plates does not change, force between the plates remain constant.