The separation between the plates of a charged parallel-plate capacitor is increased. Which of the following quantities will change?

When we increase the separation between the plates of a charged parallel capacitor the value of Capacitance decreases by the formula


Where,


d=separation between the plates


A=area of plates


ϵ0=absolute permittivity of vacuum


Charge on the capacitor remains unchanged because no charge transfer takes place.


Potential difference across the capacitor changes by the formula



Where,


Q= charge on the capacitor


C=capacitance


Similarly Energy across the capacitor given by



Where,


C=capacitance


V=potential difference across capacitor


So, as V changes energy stored also changes


Therefore, on increasing separation between the plates of capacitor, potential difference and energy of capacitor changes whereas charge and energy density remains the same.

1