When 1.0 × 1012 electrons are transferred from one conductor to another, a potential difference of 10V appears between the conductors. Calculate the capacitance of the two-conductor system.
Given:
n=1.0 × 1012
V= 10 V
Formula used:
1. Charge can be given by the formula
Where Q→ Charge on the capacitor
n → number of the electrons
e → electric charge of an electron =
2. The capacitance of a parallel plate Capacitor is given by
Where Q → charge on the capacitor
V → Voltage or potential difference
Putting the values in the formula 1, we get
Substitute Q and C in Formula 2), we get
Thus, the capacitance of the parallel plate capacitor is
So, if 1.0 × 1012 electrons are transferred between two conductors the capacitance of the parallel plate capacitor is F when a potential difference is 10V