In the given fig. Capacitors B and C are in parallel.

The formula for parallel combination of capacitor is

C_eq=C₁+C₂= C_A +C_B= 4 + 4 =8 μF

The formula for series combination of capacitors is

From the figure, the 8 μF is connected in series with C_eqv.

Thus, we get

Putting the values in the above equation, we get

Capacitors B and C are in parallel. C_C

System of B,C and A has the same capacitor values. So they exhibit the same potential difference between them.

Hence Voltage across A is =6V

The voltage across B and C is = 6V

The charge can be calculated as

Where

Q is the charge of the capacitor

C is the Capacitance of the capacitor

V is the voltage across the circuit

Charge flows through A is Q_A = 8×6= 48μC

Charge flows through B is Q_B= 4×6 =24μC

Charge flows through C is Q_C= 4×6 = 24μC

Charge appearing on the capacitors A, B and C is 48μC, 24μC and 24μC respectively.