The outer cylinders of two cylindrical capacitors of capacitance 2.2 μf each are kept in contact, and the inner cylinders are connected through a wire. A battery of emf 10V is connected as shown in the figure. Find the total charge supplied by the battery to the inner cylinders.
Lets take inner cylinders as A and B. and outer cylinders as A1 and B1. Inner cylinders A and B are connected through a wire. Outer cylinders kept in contact. If we draw the diagram, it will be look like as fig.
Given
capacitance C= 2.2μF
Voltage=10V
Capacitors are kept in parallel. So the potential difference across them is the same.
Formula used:
The magnitude of the charge on each capacitor is
Where
Q is the charge of the capacitor
C is the Capacitance of the capacitor
V is the voltage across the capacitor
Inner cylinders of the capacitor are connected to the positive terminal of the battery. So the charge on each of them is +22μC
Net charge on the inner cylinders is = 22μC+22μC= +44μC
Note: If it is asked for a charge on outer cylinders of the capacitor. A net charge will be equal to -44μC because they are connected to the negative terminal of the battery).