If the above capacitor is connected across a 6.0V battery, find

a) the charge supplied by the battery,


b) the induced charge on the dielectric and


c) the net charge appearing on one of the coated surfaces.


Given-



Capacitance of the capacitor, C = 1.42 nF
Dielectric constant, k = 4
Voltage of the battery connected, V = 6 V


a)The charge supplied by the battery is given by-


We know from definition of capacitance, charge q on capacitor is given by -


q=CV


Where C= capacitance and V = applied voltage.




1)


b) The charge induced on the dielectric –


We know, the induced polarization charge on a dielectric material is given by-



Where,


qp = polarized charge


q = charge on the capacitance


k = dielectric constant




2)


c)The net charge appearing on one of the coated plates –


The net charge appearing will be the charge on the plat minus the charge on dielectric material


From 1) and 2)


=


1