If the above capacitor is connected across a 6.0V battery, find
a) the charge supplied by the battery,
b) the induced charge on the dielectric and
c) the net charge appearing on one of the coated surfaces.
Given-
Capacitance of the capacitor, C = 1.42 nF
Dielectric constant, k = 4
Voltage of the battery connected, V = 6 V
a)The charge supplied by the battery is given by-
We know from definition of capacitance, charge q on capacitor is given by -
q=CV
Where C= capacitance and V = applied voltage.
⇒
1)
b) The charge induced on the dielectric –
We know, the induced polarization charge on a dielectric material is given by-
Where,
qp = polarized charge
q = charge on the capacitance
k = dielectric constant
2)
c)The net charge appearing on one of the coated plates –
The net charge appearing will be the charge on the plat minus the charge on dielectric material
From 1) and 2)
=