An air-filled parallel-plate capacitor is to be constructed which can store 12 μC of charge when operated at 1200V. What can be the minimum plate area of the capacitor? The dielectric strength of air is 3 × 10 6 V m –1 .

Question

Philoid · Accepted Answer

Given,

Q = 12μc =

V = 1200V

dielectric strength, b = 3 x 10⁶V/m

Plate Area can be calculated as follows –

The separation between the plates of the capacitor is given by-

where v is the applied voltage and b is the dielectric strength

Now, the capacitance of the capacitor is given by

where Q is the charge stored and V is the voltage applied.

We know, capacitance c is given by-

Where,

A= Plate Area

d= separation between the plates,

∈₀ = Permittivity of free space = 8.854 × 10^-12 m^-3 kg^-1 s⁴ A²

Thus, the area of the plates is given by –

⇒ A= m²

=0.45 m²

An air-filled parallel-plate capacitor is to be constructed which can store 12 μC of charge when operated at 1200V. What can be the minimum plate area of the capacitor? The dielectric strength of air is 3 × 106 V m–1.

An air-filled parallel-plate capacitor is to be constructed which can store 12 μC of charge when operated at 1200V. What can be the minimum plate area of the capacitor? The dielectric strength of air is 3 × 10⁶ V m^–1.