Given-

Current through the wire, i = 2 A
Resistance of the wire, R = 25 Ω
Time taken, t = 1 min = 60 s
We know Joule’s heating effect, heat developed across the wire,

where,

I =current

R = resistance of the resistor

t = time for which current is flowing

Putting the value in the above formula, we get

⇒ = 2 × 2 × 25 × 60= 100 × 60 J = 6000 J