A brass plate having surface area 200 cm2 on one side is electroplated with 0.10 mm thick silver layers on both sides using a 15 A current. Find the time taken to do the job. The specific gravity of silver is 10.5 and its atomic weight is 107.9 g mol–1.
Given-
Current passing, i = 15 A
Surface area of the plate = 200 cm2,
Thickness of silver deposited= 0.1 mm = 0.01 cm
Volume of Ag deposited on one side = 200 × 0.01 cm3 = 2 cm3
Volume of Ag deposited on both side = 2 ×2 cm3 = 4 cm3
The specific gravity of silver = 10.5
Atomic weight = 107.9 g mol–1
Now, mass of silver deposited, m can be calculated
m = Volume × Specific gravity × 1000
putting the value in the above formula, we get
= 4 × 10-3 × 10.5 ×1000
= 42 kg
Using the formula, from faraday’s law of electrolysis –
where,
m = the mass of the substance deposited on the electrode
z=electrochemical equivalence
i=current passing
t=time taken
Substituting the values