Figure shows two identical triode tubes connected in parallel. The anodes are connected together, the grids are connected together and the cathodes are connected together. Show that the equivalent plate resistance is half to the individual plate resistance. The equivalent mutual conductance is double the individual mutual conductance and the equivalent amplification factor is the same as the individual amplification factor


Given the anodes are connected together, the grids are connected together and the cathodes are connected together i.e. two triodes have same voltage and same current which means rP1 = rP2=r


Here the equivalent resistance,



i.e., the equivalent plate resistance is half to the individual plate resistance.


Let gm1 and gm2 be the individual conductance.


From figure, gm1 = gm1 = g. As two triodes are parallel i.e. equivalent conductance



i.e. The equivalent mutual conductance is double the individual mutual conductance


Now,


Also,



I.e. the equivalent amplification factor is the same as the individual amplification factor


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