Intensity of light is doubled and therefore the photocurrent will be doubled since. Also, at the same time, the frequency is doubled and therefore, the stopping potential increased by more than double. The increase in stopping potential decreases the photocurrent. Hence taking the above combined effect, the saturation current (photocurrent) thus remains almost same. So, the statement A is true.

The maximum kinetic energy of photoelectron is given by

Where, =Planck’s constant; =frequency of the light and =Work function of the metal

Now, if frequency is doubled, the maximum kinetic energy is

Multiplying 2 on both sides of equation (1) and comparing with equation (2), we get

Therefore, we conclude from above equation that the maximum kinetic energy will be more than double. Hence, statement B is false.