A proton and an electron are accelerated by the same potential difference. Let λ e and λ p denote the de Broglie wavelengths of the electron and the proton respectively.

Question

Philoid · Accepted Answer

The de Broglie wavelength is given by

Where =Planck’s constant; =mass of the particle; =momentum and =velocity of the particle

Mass of electron kg; mass of proton kg

.

Therefore, the wavelength of electron is greater than the wavelength of proton

A proton and an electron are accelerated by the same potential difference. Let λe and λp denote the de Broglie wavelengths of the electron and the proton respectively.

A proton and an electron are accelerated by the same potential difference. Let λ_e and λ_p denote the de Broglie wavelengths of the electron and the proton respectively.