Find the maximum kinetic energy of the photoelectrons ejected when light of wavelength 350 nm is incident on a cesium surface. Work function of cesium = 1.9 eV.
Given, wavelength λ =350nm =350 ×
m
Work function of cesium Ф =1.9eV
From Einstein photoelectric equation,
hf=Kmax +Ф
where Kmax is maximum kinetic energy,
h is Planck’s constant
f is frequency (f=c/λ where c is speed of light and
λ is the wavelength of light).
∴ 
⇒ 
⇒ 
⇒ 
1