The electric field associated with a monochromatic beam becomes zero 1.2 × 10 15 times per second. Find the maximum kinetic energy of the photoelectrons when this light falls on a metal surface whose work function is 2.0 eV.

Question

Philoid · Accepted Answer

NOTE: In one complete oscillation electric field become

zero twice.

Therefore, if electric field becomes zero times

per second, then number of oscillations per second will

be =

∴ Frequency of the monochromatic light will be Hz

From Einstein’s photoelectric equation, hf=Kmax +Ф

Where h is Planck’s constant,

f is the frequency of light,

Kmax is the maximum kinetic energy,

Ф is the work function

∴ putting the values in the equation we have,

⇒

∴ Maximum kinetic energy, Kmax = J.

The electric field associated with a monochromatic beam becomes zero 1.2 × 1015 times per second. Find the maximum kinetic energy of the photoelectrons when this light falls on a metal surface whose work function is 2.0 eV.

The electric field associated with a monochromatic beam becomes zero 1.2 × 10¹⁵ times per second. Find the maximum kinetic energy of the photoelectrons when this light falls on a metal surface whose work function is 2.0 eV.