The electric field at a point associated with a light wave is E = (100 V m–1) sin [(3.0 × 1015 s–1) t] sin [(6.0 × 1015 s–1) t]. If this light falls on a metal surface having a work function of 2.0 eV, what will be the maximum kinetic energy of the photoelectrons?
Given, work function Ф =2 eV
Solving the above equation using formula,
∴
From the above equation there are two values of W
∴ for maximum kinetic energy W should be maximum
∵ =
And also from Einstein’s photoelectric equation,
⇒
∴ Kinetic energy will be maximum when f (frequency) is
Maximum and f will be maximum when W is maximum.
⇒
⇒
K= 3.93 eV.