The electric field at a point associated with a light wave is E = (100 V m–1) sin [(3.0 × 1015 s–1) t] sin [(6.0 × 1015 s–1) t]. If this light falls on a metal surface having a work function of 2.0 eV, what will be the maximum kinetic energy of the photoelectrons?

Given, work function Ф =2 eV


Solving the above equation using formula,




From the above equation there are two values of W



for maximum kinetic energy W should be maximum


=


And also from Einstein’s photoelectric equation,




Kinetic energy will be maximum when f (frequency) is


Maximum and f will be maximum when W is maximum.




K= 3.93 eV.


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