A monochromatic light source of intensity 5 mW emits 8 × 10 15 photons per second. This light ejects photoelectrons from a metal surface. The stopping potential for this setup is 2.0 V. Calculate the work function of the metal.

Question

Philoid · Accepted Answer

Given, intensity I =5mW,

No. of photons emitted per second n=

Stopping potential V =2V

From Einstein’s photoelectric equation,

⇒ work function

⇒

=

∴ Work function Ф =1.906eV

A monochromatic light source of intensity 5 mW emits 8 × 1015 photons per second. This light ejects photoelectrons from a metal surface. The stopping potential for this setup is 2.0 V. Calculate the work function of the metal.

A monochromatic light source of intensity 5 mW emits 8 × 10¹⁵ photons per second. This light ejects photoelectrons from a metal surface. The stopping potential for this setup is 2.0 V. Calculate the work function of the metal.