A small piece of cesium metal (ϕ = 1.9 eV) is kept at a distance of 20 cm from a large metal plate having a charge density of 1.0 × 10–9 C m–2 on the surface facing the cesium piece. A monochromatic light of wavelength 400 nm is incident on the cesium piece. Find the minimum and the maximum kinetic energy of the photoelectrons reaching the large metal plate. Neglect any change in electric field due to the small piece of cesium present.
Given, work function
Charge density
Distance d=20cm
Wavelength λ=400nm
We know that electric potential due to charged plate
is given by ,
where E is the electric field due to charged plate
and d is the distance between two plates
=
= 59V
Now, from Einstein’s photoelectric equation
⇒
Now putting the values of h, c, λ, Ф we get
⇒
⇒
⇒
∴
∵ ≪≪V
∴ Minimum kinetic energy required to reach the large
Metal =22.6eV
Next, maximum kinetic energy