Name three oxoacids of nitrogen. Write the disproportionation reaction of that oxoacid of nitrogen in which nitrogen is in +3 oxidation state.

there are three oxoacids of nitrogen.

1. Nitric acid(HNO3)


2. Nitrous acid (HNO2)


3. Hyponitrous acid (H2N2O1)


+ 3 oxidation is shown by HNO2, Therefore it undergoes disproportion reaction,


To calculate oxidation state, consider the oxidation state of N is x.


3HNO2 HNO3 + 2NO +H2O


Oxidation state of nitrogen in HNO2 is +3


X + (+1) +2*(-2) = 0, x= +3


Oxidation state of nitrogen in HNO3 is +5


X + (+1) + 3*(-2) = 0, x= 5


Oxidation state of nitrogen in NO is +2


X + (-2) = 0, x =2


Therefore +3 oxidation state changes to +5 and +2 oxidation states


1