The value of C P – C V is 1.00 R for a gas sample in state A and is 1.08R in state B. Let P A , P B denote the pressures and T A, and T B denote the temperatures of the states A and B respectively. Most likely

Question

Philoid · Accepted Answer

For gas in state A, C_p - C_v = R. This represents an ideal gas. Now, for an ideal gas, we require very high temperature and very low pressure compared to a real gas

For gas in state B, C_p - C_v = 1.08R, which represents a real gas. Since gas A was ideal, its pressure must be much lower than that of B and temperature must be much higher than that of A.

Hence, we require the condition p_A < p_B and T_A > T_B. This is given by option (a).

Options (b), (c) and (d) are incorrect because none of those satisfies the conditions for an ideal gas.

The value of CP – CV is 1.00 R for a gas sample in state A and is 1.08R in state B. Let PA, PB denote the pressures and TA, and TB denote the temperatures of the states A and B respectively. Most likely

The value of C_P – C_V is 1.00 R for a gas sample in state A and is 1.08R in state B. Let P_A, P_B denote the pressures and T_A, and T_B denote the temperatures of the states A and B respectively. Most likely