Let T_{a} and T_{b} be the final temperatures of the samples A and B respectively in the previous question.

Since sample B undergoes isothermal expansion, its temperature remains constant = T_{b}.

For an adiabatic process, since the heat supplied is 0, the internal energy will change by an amount dU = nC_{v}dT,

where dU = change in internal energy

n = number of moles

C_{v} = specific heat capacity at constant volume

dT = change in temperature

This change in internal energy will compensate for the constancy in heat.

Sample B is undergoing expansion through an isothermal process; its initial and final temperatures will be the same.

Sample A will expand at the cost of its internal energy.

Therefore, the final temperature will be less than the initial temperature,

since dU < 0 => dT < 0.

T_{b}-T_{a}<0

T_{b}>T_{a} or T_{a}<T_{b}

Hence, we get T_{a}>T_{b}.

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