An amount Q of heat is added to a monatomic ideal gas in a process in which the gas performs a work Q/2 on its surrounding. Find the molar heat capacity for the process.

**Given:** Amount of heat added(dQ) = Q

Amount of work done(dW) = Q/2.

**Formula used:**

dQ(heat) = dU(internal energy) + dW(work done).

Here, heat = Q and Work = Q/2(given)

=> .

We can write U = nC_{v}dT and Q = nCdT, where n = no of moles, C_{v} = specific heat capacity at constant volume(when dQ = dU), C = molar heat capacity and dT = change in temperature.

Therefore, => C = 2C_{v}.

For a monoatomic ideal gas, we know that C_{v} = (3R/2) J/kg/mol,

Where R = universal gas constant = 8.314 J/kg/mol

Therefore, C = 2*(3R/2) = 3R J/kg/mol. (Ans)

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