In Joly’s differential steam calorimeter, 3g of an ideal gas is contained in a rigid closed sphere at 20°C. The sphere is heated by steam at 100°C and it is found that an extra 0.095 g of steam has condensed into water as the temperature of the gas becomes constant. Calculate the specific heat capacity of the gas in J g^–1 K^–1. The latent heat of vaporization of water = 540 cal g^–1.
Here,

m1 = Mass of gas present = 3 g, θ1 = 20°C, θ2 = 100°C

m2 = Mass of steam condensed = 0.095 g, L = 540 Cal/g = 540 × 4.2 J/g

In Joly’s differential steam calorimeter,

Question

Here,

m1 = Mass of gas present = 3 g, θ1 = 20°C, θ2 = 100°C

m2 = Mass of steam condensed = 0.095 g, L = 540 Cal/g = 540 × 4.2 J/g

In Joly’s differential steam calorimeter,

Philoid · Accepted Answer

Here,

m1 = Mass of gas present = 3 g, θ1 = 20°C, θ2 = 100°C

m2 = Mass of steam condensed = 0.095 g, L = 540 Cal/g = 540 × 4.2 J/g

In Joly’s differential steam calorimeter,