Suppose all the electrons of 100g water are lumped together to form a negatively charged particle and all the nuclei are lumped together to form a positively charged particle. If these two particles are placed 10.0 cm away from each other, find the force of attraction between them. Compare it with your weight.
Given:
Mass of water , 
Molar mass of water 
Moles of water in 100g of water = 
Number of electrons in 1 molecule of water = 2 times one electron each in hydrogen atom + 8 electrons in oxygen atom = 10 electrons
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Formulas used:
The relation between molar mass M, mass of sample m and number of moles of sample n is given by:
1 mol of “something” contains NA number of “something”.
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Number of electrons in 1 mol of electrons 
= 
Number of electrons in 100 g of water
Negative charge on one electron = 
Total negative charge 
We have,
Charges: 
Distance of separation, 
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Formula used:
By Coulomb’s law, the electric force is given by:
Where ϵ0 is the permittivity of free space
k is the electrostatic constant
q1 and q2 are the magnitude of charges
r is the distance of separation between the charges
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The magnitude of electric force is:
Let my mass m be 70 kg.
The electric force between the two charges is about 1022 times my weight!