An aromatic compound ‘A’ (Molecular formula C8H8O) gives positive 2, 4-DNP test. The compound gives a yellow precipitate of compound ‘B’ on treatment with iodine and sodium hydroxide solution. It does not give Tollen’s or Fehling’s test. On drastic oxidation with potassium permanganate it forms a carboxylic acid ‘C’ (Molecular formula C7H6O2) which is also formed along with the yellow compound in the above reaction. Identify compounds A, B and C and write all the reactions involved.
OR
An organic compud ‘A’ (C3H4) on hyration in presence of H2SO4/HgSO4 gives compound ‘B’ (C3H6O). Compound ‘B’ gives white crystalline product (D) with sodium hydrogensulphite. It gives negative Tollen’s test and positive iodoform’s test. On drastic oxidation ‘B’ gives compound ‘C’ (C2H4O2) along with formic acid. Identify compounds ‘A’, ‘B’ and ‘C’ and explain all the reactions.
The compound is Methyl Benzoate(A) which gives the 2,4 DNP test.
These are the compounds A, B, C with the following reactions.
OR
The reaction mechanism involves the following steps:
It is given that B gives negative tollents teat which means it is a Ketone.
The positive iodoform test suggest it has a structure similar to
Thus the compound B is propanone (common name acetone). It on the oxidation give acetic acid (compound C )and formic acid.