A first order reaction is 50% completed in 1.26 × 1014 s. How much time would it take for 100% completion?

Given, t1/2=1.261014 we know the reaction is a first order

t1/2=.693/k ……..for first-order reaction


using above given value we can find k



For 100% completion



At 100% completion R=0 so



Thus Option (iv) is correct.

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