White phosphorus reacts with chlorine and the product gets hydrolysed in the presence of water to produce HCl. Calculate the mass of HCl obtained by the hydrolysis of the product formed by the reactions of 62 g of white phosphorus with chlorine in the presence of water.

P4 + 6Cl2 → 4PCl3


PCl3 + 3H2O → H3PO3 + 3HCl} x 4


Overall reaction will be,


P4 + 6Cl2 + 12H2O → 4 H3PO3 + 12HCl


1 mole of white phosphorus produces 12 moles of HCl…………..a)


1 mole of HCl weighs 36.5g,


so weight of 12moles will be, 12 x 36.5=438g……………………………i)


1 mole of white phosphorus weighs 124 g………………….ii)


Equation a) implies that 124g of phosphorus is used to produce 438g of HCl


So 1g of phosphorus would give= 438/124 g of HCl


62 g would give= (438/124) x 62 = 219 g of HCl




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