Consider a p-n junction diode having the characteristic i= i0(eeV/kT – 1) where i0 = 20 μA. The diode is operated at T = 300 K.

(a) Find the current through the diode when a voltage of 300 mV is applied across it in forward bias.


(b) At what voltage does the current double?


Given, i0 =20 μA =20×10-6 A
And temperature, T=300K

a) Forward biasing voltage, V=300mV
According to the current diode equation,





b) Now the current has doubled, i.e. i = 4 A


According to the current diode equation,


i = i0 (eeV/kT – 1)





Taking log both sides,




V= 318mV


1