Consider a p-n junction diode having the characteristic i= i0(eeV/kT – 1) where i0 = 20 μA. The diode is operated at T = 300 K.
(a) Find the current through the diode when a voltage of 300 mV is applied across it in forward bias.
(b) At what voltage does the current double?
Given, i0 =20 μA =20×10-6 A
And temperature, T=300K
a) Forward biasing voltage, V=300mV
According to the current diode equation,
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b) Now the current has doubled, i.e. i = 4 A
According to the current diode equation,
• i = i0 (eeV/kT – 1)
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Taking log both sides,
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• V= 318mV