Yes.

Let the LCR circuit be connected across an AC supply of voltage … (i)

Now, the impedance in an AC circuit is given by

…. (ii)

where R = resistance, X_L = inductive reactance,

X_c = capacitive reactance,

ω = angular frequency of oscillation of current,

L = inductance,

C = capacitance

Hence, the current in the circuit is given by … (iii),

where V = voltage,

Z = impedance

⇒ … (iv)

Now, at resonance, ⇒ --------------(v)

Substituting (v) in (iv), we get

Current at resonance : … (vi)

Hence, at resonance, voltage across the inductor

⇒ … (vii)

where I_res = current at resonance, X_L = inductive reactance, V = source voltage = V₀sinωt, where V₀ = peak voltage, ω = angular frequency, t = time, R = resistance, L = inductance

Since ω = angular frequency is always greater than equal to 1,

Therefore, voltage across the inductor V_L will be greater than the source voltage V if > 1. (Ans)