An alternating current peak value 14 A is used to heat a metal wire. To produce the same heating effect, a constant current i can be used where i is

Question

Philoid · Accepted Answer

To produce the same heating effect, the constant current required(i) will be the root mean square(rms) current(irms)

Hence, where i₀ = peak current = 14 A

=>i = (14/√2) A = 9.899 A which is about 10 A. (Ans)