A capacitor of capacitance 10 μF is connected to an oscillator giving an output voltage ϵ = (10V) sin ωt. Find the peak currents in the circuit for ω = 10 s –1 , 100 s –1 , 500 s –1 , 1000 s –1 .

Question

Philoid · Accepted Answer

Capacitance of the capacitor C=10 μF,

Output voltage of the oscillator ϵ = (10V) sin ωt.

On comparing the output voltage of the oscillator with

We get Peak voltage

For a capacitive circuit,

Reactance,

Here, is angular frequency,

C is capacitance of capacitor,

Peak current

{a} At

Peak current

{b} At

Peak current

{c} At

Peak current

{d} At

Peak current

A capacitor of capacitance 10 μF is connected to an oscillator giving an output voltage ϵ = (10V) sin ωt. Find the peak currents in the circuit for ω = 10 s–1, 100 s–1, 500 s–1, 1000 s–1.

A capacitor of capacitance 10 μF is connected to an oscillator giving an output voltage ϵ = (10V) sin ωt. Find the peak currents in the circuit for ω = 10 s^–1, 100 s^–1, 500 s^–1, 1000 s^–1.