A resistor of resistance 100 Ω is connected to an AC source ϵ = (12 V) sin (250 π s –1 ) t. Find the energy dissipated as heat during t = 0 to t = 1.0 ms.

Question

Philoid · Accepted Answer

Given: Resistance (R) =100 Ω

Source emf ϵ = (12 V) sin (250 π s^–1) t

T=1.0 ms =10^-3 s.t

Then, energy dissipated (E) will be

Since,

On integrating,

A resistor of resistance 100 Ω is connected to an AC source ϵ = (12 V) sin (250 π s–1) t. Find the energy dissipated as heat during t = 0 to t = 1.0 ms.

A resistor of resistance 100 Ω is connected to an AC source ϵ = (12 V) sin (250 π s^–1) t. Find the energy dissipated as heat during t = 0 to t = 1.0 ms.