An inductor-coil, a capacitor and an AC source of rms voltage 24 V are connected in series. When the frequency of the source is varied, a maximum rms current of 6.0 A is observed. If this inductor coil is connected to a battery of emf 12 V and internal resistance 4.0Ω, what will be the current?

Question

Philoid · Accepted Answer

Given that rms voltage =24V

Internal resistance, r= 4 ohm

Rms current =6A

Then, rms resistance will be

If this inductor coil is connected to a battery of emf E= 12 V and internal resistance r’ = 4.0Ω, then the steady current will be

Since, net resistance R’ = (R + r’) = 4+4 =8 ohm.

Therefore, the steady current (I) is