A conducting square loop of side ℓ and resistance R moves in its plane with a uniform velocity v perpendicular to one of its sides. A uniform and constant magnetic field B exists along the perpendicular to the plane of the loop, as shown in the figure. The current induced in the loop is

Question

Philoid · Accepted Answer

if we draw the equivalent circuit, it will be look like

The formula used: The emf induces across the ends AB and CD is given by

Where E is the emf

V is the velocity

B is the magnetic field

l is the length

Apply KVL in the loop in fig(b).

Here the current I become zero means that there is no current induced in the loop. So the current induced in the loop will be zero.